Ninja
edit_distance.cc
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1 // Copyright 2011 Google Inc. All Rights Reserved.
2 //
3 // Licensed under the Apache License, Version 2.0 (the "License");
4 // you may not use this file except in compliance with the License.
5 // You may obtain a copy of the License at
6 //
7 // http://www.apache.org/licenses/LICENSE-2.0
8 //
9 // Unless required by applicable law or agreed to in writing, software
10 // distributed under the License is distributed on an "AS IS" BASIS,
11 // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
12 // See the License for the specific language governing permissions and
13 // limitations under the License.
14 
15 #include "edit_distance.h"
16 
17 #include <algorithm>
18 #include <vector>
19 
20 using namespace std;
21 
22 int EditDistance(const StringPiece& s1,
23  const StringPiece& s2,
24  bool allow_replacements,
25  int max_edit_distance) {
26  // The algorithm implemented below is the "classic"
27  // dynamic-programming algorithm for computing the Levenshtein
28  // distance, which is described here:
29  //
30  // http://en.wikipedia.org/wiki/Levenshtein_distance
31  //
32  // Although the algorithm is typically described using an m x n
33  // array, only one row plus one element are used at a time, so this
34  // implementation just keeps one vector for the row. To update one entry,
35  // only the entries to the left, top, and top-left are needed. The left
36  // entry is in row[x-1], the top entry is what's in row[x] from the last
37  // iteration, and the top-left entry is stored in previous.
38  int m = s1.len_;
39  int n = s2.len_;
40 
41  vector<int> row(n + 1);
42  for (int i = 1; i <= n; ++i)
43  row[i] = i;
44 
45  for (int y = 1; y <= m; ++y) {
46  row[0] = y;
47  int best_this_row = row[0];
48 
49  int previous = y - 1;
50  for (int x = 1; x <= n; ++x) {
51  int old_row = row[x];
52  if (allow_replacements) {
53  row[x] = min(previous + (s1.str_[y - 1] == s2.str_[x - 1] ? 0 : 1),
54  min(row[x - 1], row[x]) + 1);
55  }
56  else {
57  if (s1.str_[y - 1] == s2.str_[x - 1])
58  row[x] = previous;
59  else
60  row[x] = min(row[x - 1], row[x]) + 1;
61  }
62  previous = old_row;
63  best_this_row = min(best_this_row, row[x]);
64  }
65 
66  if (max_edit_distance && best_this_row > max_edit_distance)
67  return max_edit_distance + 1;
68  }
69 
70  return row[n];
71 }
const char * str_
Definition: string_piece.h:66
StringPiece represents a slice of a string whose memory is managed externally.
Definition: string_piece.h:25
size_t len_
Definition: string_piece.h:67
int EditDistance(const StringPiece &s1, const StringPiece &s2, bool allow_replacements, int max_edit_distance)